√ cv=r/y-1 266350-Cv=r/y-1

This video will derive expressions for molar specific heat at constant volume and pressureQuestion Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!This video will derive expressions for molar specific heat at constant volume and pressure

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Cv=r/y-1

Cv=r/y-1-Bonjour, Les deux s'appellent "capacité thermique", sauf que Cv est la capacité thermique molaire et cv la capacité thermique massique La première vaut Cv=nR/(y1) (y pour gamma ) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/(y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air par exemple) On a donc r=R/M (masse molaire bien sûr) et cv=Cv/MAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators

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Question Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!Learn with content Watch learning videos, swipe through stories, and browse through concepts1c) Why is the expression w = Pdv restricted to reversible processes?

1c) Why is the expression w = Pdv restricted to reversible processes?Cp It is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 Degree Celsius are 1 Kelvin at constant pressure Cv it is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 DegreThanks for your help Answers and Replies Related Introductory Physics Homework Help News on Physorg

See the answer Show transcribed image text Expert Answer 100% (1 rating)See the answer Show transcribed image text Expert Answer 100% (1 rating)Then i find cv by cv=R/(Y1) cv=7858 thus dw= (de) where de=cv(T2T1) my answer for the work done is kJ/kg however the books answer is 3013 Kj/kj what am i doing wrong?

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Molar Specific Heat Of Ideal Gases Ppt Download

Then i find cv by cv=R/(Y1) cv=7858 thus dw= (de) where de=cv(T2T1) my answer for the work done is kJ/kg however the books answer is 3013 Kj/kj what am i doing wrong?See the answer Show transcribed image text Expert Answer 100% (1 rating)Learn with content Watch learning videos, swipe through stories, and browse through concepts

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Assuming you are from engineering background, I would like to first highlight that, py^gamma=constant represents reversible adiabatic process Reversible adiabatic process physically represents an isentropic process (s=c, ds=0) Tds equation in geAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators1d) Show that for an ideal gas Cp=yR/(Y1), Cv=R/(Y1) and CpCv=R Get more help from Chegg Get 11 help now from expert Mechanical Engineering tutors

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La première vaut Cv=nR/ (y1) (y pour gamma) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/ (y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air parThis video will derive expressions for molar specific heat at constant volume and pressure1d) Show that for an ideal gas Cp=yR/(Y1), Cv=R/(Y1) and CpCv=R Get more help from Chegg Get 11 help now from expert Mechanical Engineering tutors

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Assuming you are from engineering background, I would like to first highlight that, py^gamma=constant represents reversible adiabatic process Reversible adiabatic process physically represents an isentropic process (s=c, ds=0) Tds equation in geAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us CreatorsQuestion Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!

Ppt P Rt 11 1 R R Univ M Mole Du C V Dt 11 2 Dh C P Dt 11 3 Powerpoint Presentation Id

Molar Specific Heat Of Ideal Gases Ppt Download

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Incoming Term: cv=r/y-1,