√ cv=r/y-1 266350-Cv=r/y-1

This video will derive expressions for molar specific heat at constant volume and pressureQuestion Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!This video will derive expressions for molar specific heat at constant volume and pressure

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Cv=r/y-1

Cv=r/y-1-Bonjour, Les deux s'appellent "capacité thermique", sauf que Cv est la capacité thermique molaire et cv la capacité thermique massique La première vaut Cv=nR/(y1) (y pour gamma ) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/(y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air par exemple) On a donc r=R/M (masse molaire bien sûr) et cv=Cv/MAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators

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Question Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!Learn with content Watch learning videos, swipe through stories, and browse through concepts1c) Why is the expression w = Pdv restricted to reversible processes?

1c) Why is the expression w = Pdv restricted to reversible processes?Cp It is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 Degree Celsius are 1 Kelvin at constant pressure Cv it is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 DegreThanks for your help Answers and Replies Related Introductory Physics Homework Help News on Physorg

See the answer Show transcribed image text Expert Answer 100% (1 rating)See the answer Show transcribed image text Expert Answer 100% (1 rating)Then i find cv by cv=R/(Y1) cv=7858 thus dw= (de) where de=cv(T2T1) my answer for the work done is kJ/kg however the books answer is 3013 Kj/kj what am i doing wrong?

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Then i find cv by cv=R/(Y1) cv=7858 thus dw= (de) where de=cv(T2T1) my answer for the work done is kJ/kg however the books answer is 3013 Kj/kj what am i doing wrong?See the answer Show transcribed image text Expert Answer 100% (1 rating)Learn with content Watch learning videos, swipe through stories, and browse through concepts

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Assuming you are from engineering background, I would like to first highlight that, py^gamma=constant represents reversible adiabatic process Reversible adiabatic process physically represents an isentropic process (s=c, ds=0) Tds equation in geAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators1d) Show that for an ideal gas Cp=yR/(Y1), Cv=R/(Y1) and CpCv=R Get more help from Chegg Get 11 help now from expert Mechanical Engineering tutors

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La première vaut Cv=nR/ (y1) (y pour gamma) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/ (y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air parThis video will derive expressions for molar specific heat at constant volume and pressure1d) Show that for an ideal gas Cp=yR/(Y1), Cv=R/(Y1) and CpCv=R Get more help from Chegg Get 11 help now from expert Mechanical Engineering tutors

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Assuming you are from engineering background, I would like to first highlight that, py^gamma=constant represents reversible adiabatic process Reversible adiabatic process physically represents an isentropic process (s=c, ds=0) Tds equation in geAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us CreatorsQuestion Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!

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Thanks for your help Answers and Replies Related Introductory Physics Homework Help News on PhysorgLearn with content Watch learning videos, swipe through stories, and browse through conceptsBonjour, Les deux s'appellent "capacité thermique", sauf que Cv est la capacité thermique molaire et cv la capacité thermique massique La première vaut Cv=nR/(y1) (y pour gamma ) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/(y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air par exemple) On a donc r=R/M (masse molaire bien sûr) et cv=Cv/M

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Cp It is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 Degree Celsius are 1 Kelvin at constant pressure Cv it is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 Degre

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